72=1/2(x+2)(2x+16)

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Solution for 72=1/2(x+2)(2x+16) equation: 



72=1/2(x+2)(2x+16)

We move all terms to the left:

72-(1/2(x+2)(2x+16))=0



Domain of the equation: 2(x+2)(2x+16))!=0

x∈R



We multiply parentheses ..

-(1/2(+2x^2+16x+4x+32))+72=0

We multiply all the terms by the denominator


-(1+72*2(+2x^2+16x+4x+32))=0



We calculate terms in parentheses: -(1+72*2(+2x^2+16x+4x+32)), so:

1+72*2(+2x^2+16x+4x+32)

determiningTheFunctionDomain
72*2(+2x^2+16x+4x+32)+1

Wy multiply elements

144x(++1

We use the square of the difference formula

144x(+1

Back to the equation:

-(144x(+1)



We add all the numbers together, and all the variables

-(144x1=0

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