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2x+2-6x=8-2(2x+3)
We move all terms to the left:
2x+2-6x-(8-2(2x+3))=0
We add all the numbers together, and all the variables
-4x-(8-2(2x+3))+2=0
We calculate terms in parentheses: -(8-2(2x+3)), so:We get rid of parentheses
8-2(2x+3)
determiningTheFunctionDomain -2(2x+3)+8
We multiply parentheses
-4x-6+8
We add all the numbers together, and all the variables
-4x+2
Back to the equation:
-(-4x+2)
-4x+4x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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