12(7x-3)+5(8+12x)+2(42x-18)=4200

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Solution for 12(7x-3)+5(8+12x)+2(42x-18)=4200 equation: 



12(7x-3)+5(8+12x)+2(42x-18)=4200

We move all terms to the left:

12(7x-3)+5(8+12x)+2(42x-18)-(4200)=0

We add all the numbers together, and all the variables

12(7x-3)+5(12x+8)+2(42x-18)-4200=0

We multiply parentheses

84x+60x+84x-36+40-36-4200=0

We add all the numbers together, and all the variables

228x-4232=0

We move all terms containing x to the left, all other terms to the right

228x=4232

x=4232/228

x=18+32/57

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