8y-5(y-3)=42

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Solution for 8y-5(y-3)=42 equation: 



8y-5(y-3)=42

We move all terms to the left:

8y-5(y-3)-(42)=0

We multiply parentheses

8y-5y+15-42=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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