2x+1=(x+1)+(3x-2)

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Solution for 2x+1=(x+1)+(3x-2) equation: 



2x+1=(x+1)+(3x-2)

We move all terms to the left:

2x+1-((x+1)+(3x-2))=0



We calculate terms in parentheses: -((x+1)+(3x-2)), so:

(x+1)+(3x-2)

We get rid of parentheses

x+3x+1-2

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We get rid of parentheses

2x-4x+1+1=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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