.1n+.06(20000-n)=1500

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Solution for .1n+.06(20000-n)=1500 equation: 



.1n+.06(20000-n)=1500

We move all terms to the left:

.1n+.06(20000-n)-(1500)=0

We add all the numbers together, and all the variables

.1n+.06(-1n+20000)-1500=0

We multiply parentheses

.1n-0.06n+1200-1500=0

We add all the numbers together, and all the variables

0.04n-300=0

We move all terms containing n to the left, all other terms to the right

0.04n=300

n=300/0.04

n=7500

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