(3x+4)=(x-3)+(5x-4)

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Solution for (3x+4)=(x-3)+(5x-4) equation: 



(3x+4)=(x-3)+(5x-4)

We move all terms to the left:

(3x+4)-((x-3)+(5x-4))=0

We get rid of parentheses

3x-((x-3)+(5x-4))+4=0



We calculate terms in parentheses: -((x-3)+(5x-4)), so:

(x-3)+(5x-4)

We get rid of parentheses

x+5x-3-4

We add all the numbers together, and all the variables

6x-7

Back to the equation:

-(6x-7)



We get rid of parentheses

3x-6x+7+4=0

We add all the numbers together, and all the variables

-3x+11=0

We move all terms containing x to the left, all other terms to the right

-3x=-11

x=-11/-3

x=3+2/3

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