2x+10/3x+9=0

Solution for 2x+10/3x+9=0 equation:

2x+10/3x+9=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We multiply all the terms by the denominator


2x*3x+9*3x+10=0

Wy multiply elements

6x^2+27x+10=0

a = 6; b = 27; c = +10;
Δ = b2-4ac
Δ = 272-4·6·10
Δ = 489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{489}}{2*6}=\frac{-27-\sqrt{489}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{489}}{2*6}=\frac{-27+\sqrt{489}}{12}
$