(t+4)+(t-1)+(t-3)=19

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Solution for (t+4)+(t-1)+(t-3)=19 equation: 



(t+4)+(t-1)+(t-3)=19

We move all terms to the left:

(t+4)+(t-1)+(t-3)-(19)=0

We get rid of parentheses

t+t+t+4-1-3-19=0

We add all the numbers together, and all the variables

3t-19=0

We move all terms containing t to the left, all other terms to the right

3t=19

t=19/3

t=6+1/3

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