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1/x+1+5/x-2=3x/(x+1)(x-2)
We move all terms to the left:
1/x+1+5/x-2-(3x/(x+1)(x-2))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+1)(x-2))!=0We add all the numbers together, and all the variables
x∈R
1/x+5/x-(3x/(x+1)(x-2))-1=0
We multiply parentheses ..
-(3x/(+x^2-2x+x-2))+1/x+5/x-1=0
We calculate fractions
We do not support expression: x^3
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