2x+(3x-10)+50=180

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Solution for 2x+(3x-10)+50=180 equation: 



2x+(3x-10)+50=180

We move all terms to the left:

2x+(3x-10)+50-(180)=0

We add all the numbers together, and all the variables

2x+(3x-10)-130=0

We get rid of parentheses

2x+3x-10-130=0

We add all the numbers together, and all the variables

5x-140=0

We move all terms containing x to the left, all other terms to the right

5x=140

x=140/5

x=28

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