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(X+6)X(X-3)=9X(X-1)
We move all terms to the left:
(X+6)X(X-3)-(9X(X-1))=0
We calculate terms in parentheses: -(9X(X-1)), so:We get rid of parentheses
9X(X-1)
We multiply parentheses
9X^2-9X
Back to the equation:
-(9X^2-9X)
-9X^2+(X+6)X(X-3)+9X=0
We add all the numbers together, and all the variables
-9X^2+9X+(X+6)X(X-3)=0
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