(Q-6)x2=10

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Solution for (Q-6)x2=10 equation: 



(-6)Q2=10

We move all terms to the left:

(-6)Q2-(10)=0

We multiply parentheses

-6Q^2-10=0

a = -6; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-6)·(-10)
Δ = -240
Delta is less than zero, so there is no solution for the equation

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