2x+(2/3)x=16

Solution for 2x+(2/3)x=16 equation:

2x+(2/3)x=16

We move all terms to the left:

2x+(2/3)x-(16)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x+(+2/3)x-16=0

We multiply parentheses

2x^2+2x-16=0

a = 2; b = 2; c = -16;
Δ = b2-4ac
Δ = 22-4·2·(-16)
Δ = 132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132}=\sqrt{4*33}=\sqrt{4}*\sqrt{33}=2\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{33}}{2*2}=\frac{-2-2\sqrt{33}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{33}}{2*2}=\frac{-2+2\sqrt{33}}{4}
$