6(3n-5)=(4n+2)+1

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Solution for 6(3n-5)=(4n+2)+1 equation: 



6(3n-5)=(4n+2)+1

We move all terms to the left:

6(3n-5)-((4n+2)+1)=0

We multiply parentheses

18n-((4n+2)+1)-30=0



We calculate terms in parentheses: -((4n+2)+1), so:

(4n+2)+1

We get rid of parentheses

4n+2+1

We add all the numbers together, and all the variables

4n+3

Back to the equation:

-(4n+3)



We get rid of parentheses

18n-4n-3-30=0

We add all the numbers together, and all the variables

14n-33=0

We move all terms containing n to the left, all other terms to the right

14n=33

n=33/14

n=2+5/14

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