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2x(x+5)-34=4(x-1)
We move all terms to the left:
2x(x+5)-34-(4(x-1))=0
We multiply parentheses
2x^2+10x-(4(x-1))-34=0
We calculate terms in parentheses: -(4(x-1)), so:We get rid of parentheses
4(x-1)
We multiply parentheses
4x-4
Back to the equation:
-(4x-4)
2x^2+10x-4x+4-34=0
We add all the numbers together, and all the variables
2x^2+6x-30=0
a = 2; b = 6; c = -30;
Δ = b2-4ac
Δ = 62-4·2·(-30)
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{69}}{2*2}=\frac{-6-2\sqrt{69}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{69}}{2*2}=\frac{-6+2\sqrt{69}}{4} $
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