6(z+2)-7z=2+10

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Solution for 6(z+2)-7z=2+10 equation: 



6(z+2)-7z=2+10

We move all terms to the left:

6(z+2)-7z-(2+10)=0

We add all the numbers together, and all the variables

6(z+2)-7z-12=0

We add all the numbers together, and all the variables

-7z+6(z+2)-12=0

We multiply parentheses

-7z+6z+12-12=0

We add all the numbers together, and all the variables

-z=0

z=0/-1

z=0

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