3(x+4)-0.2(10-x)=74

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Solution for 3(x+4)-0.2(10-x)=74 equation: 



3(x+4)-0.2(10-x)=74

We move all terms to the left:

3(x+4)-0.2(10-x)-(74)=0

We add all the numbers together, and all the variables

3(x+4)-0.2(-1x+10)-74=0

We multiply parentheses

3x+0.2x+12-2-74=0

We add all the numbers together, and all the variables

3.2x-64=0

We move all terms containing x to the left, all other terms to the right

3.2x=64

x=64/3.2

x=20

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