2x(x+15)=3+(x-7)

Solution for 2x(x+15)=3+(x-7) equation:

2x(x+15)=3+(x-7)

We move all terms to the left:

2x(x+15)-(3+(x-7))=0

We multiply parentheses

2x^2+30x-(3+(x-7))=0


We calculate terms in parentheses: -(3+(x-7)), so:

3+(x-7)

determiningTheFunctionDomain
(x-7)+3

We get rid of parentheses

x-7+3

We add all the numbers together, and all the variables

x-4

Back to the equation:

-(x-4)


We get rid of parentheses

2x^2+30x-x+4=0

We add all the numbers together, and all the variables

2x^2+29x+4=0

a = 2; b = 29; c = +4;
Δ = b2-4ac
Δ = 292-4·2·4
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{809}}{2*2}=\frac{-29-\sqrt{809}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{809}}{2*2}=\frac{-29+\sqrt{809}}{4}
$