-2(b-2)=-3+2b

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Solution for -2(b-2)=-3+2b equation: 



-2(b-2)=-3+2b

We move all terms to the left:

-2(b-2)-(-3+2b)=0

We add all the numbers together, and all the variables

-2(b-2)-(2b-3)=0

We multiply parentheses

-2b-(2b-3)+4=0

We get rid of parentheses

-2b-2b+3+4=0

We add all the numbers together, and all the variables

-4b+7=0

We move all terms containing b to the left, all other terms to the right

-4b=-7

b=-7/-4

b=1+3/4

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