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2x(5x-5)=3x-14
We move all terms to the left:
2x(5x-5)-(3x-14)=0
We multiply parentheses
10x^2-10x-(3x-14)=0
We get rid of parentheses
10x^2-10x-3x+14=0
We add all the numbers together, and all the variables
10x^2-13x+14=0
a = 10; b = -13; c = +14;
Δ = b2-4ac
Δ = -132-4·10·14
Δ = -391
Delta is less than zero, so there is no solution for the equation
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