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5x/3+2/3=1
We move all terms to the left:
5x/3+2/3-(1)=0
determiningTheFunctionDomain 5x/3-1+2/3=0
We multiply all the terms by the denominator
5x+2-1*3=0
We add all the numbers together, and all the variables
5x-1=0
We move all terms containing x to the left, all other terms to the right
5x=1
x=1/5
x=1/5
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