2v+2=-3(1+v)+5(v+1)

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Solution for 2v+2=-3(1+v)+5(v+1) equation: 



2v+2=-3(1+v)+5(v+1)

We move all terms to the left:

2v+2-(-3(1+v)+5(v+1))=0

We add all the numbers together, and all the variables

2v-(-3(v+1)+5(v+1))+2=0



We calculate terms in parentheses: -(-3(v+1)+5(v+1)), so:

-3(v+1)+5(v+1)

We multiply parentheses

-3v+5v-3+5

We add all the numbers together, and all the variables

2v+2

Back to the equation:

-(2v+2)



We get rid of parentheses

2v-2v-2+2=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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