-3j+6-5=3j+20

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Solution for -3j+6-5=3j+20 equation: 



-3j+6-5=3j+20

We move all terms to the left:

-3j+6-5-(3j+20)=0

We add all the numbers together, and all the variables

-3j-(3j+20)+1=0

We get rid of parentheses

-3j-3j-20+1=0

We add all the numbers together, and all the variables

-6j-19=0

We move all terms containing j to the left, all other terms to the right

-6j=19

j=19/-6

j=-3+1/6

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