43+(8x-20)=(10x-11)

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Solution for 43+(8x-20)=(10x-11) equation: 



43+(8x-20)=(10x-11)

We move all terms to the left:

43+(8x-20)-((10x-11))=0

We get rid of parentheses

8x-((10x-11))-20+43=0



We calculate terms in parentheses: -((10x-11)), so:

(10x-11)

We get rid of parentheses

10x-11

Back to the equation:

-(10x-11)



We add all the numbers together, and all the variables

8x-(10x-11)+23=0

We get rid of parentheses

8x-10x+11+23=0

We add all the numbers together, and all the variables

-2x+34=0

We move all terms containing x to the left, all other terms to the right

-2x=-34

x=-34/-2

x=+17

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