12(8c-5)=3c+44

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Solution for 12(8c-5)=3c+44 equation: 



12(8c-5)=3c+44

We move all terms to the left:

12(8c-5)-(3c+44)=0

We multiply parentheses

96c-(3c+44)-60=0

We get rid of parentheses

96c-3c-44-60=0

We add all the numbers together, and all the variables

93c-104=0

We move all terms containing c to the left, all other terms to the right

93c=104

c=104/93

c=1+11/93

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