2(3x+40)=32

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Solution for 2(3x+40)=32 equation:



2(3x+40)=32
We move all terms to the left:
2(3x+40)-(32)=0
We multiply parentheses
6x+80-32=0
We add all the numbers together, and all the variables
6x+48=0
We move all terms containing x to the left, all other terms to the right
6x=-48
x=-48/6
x=-8

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