7x+13-(4x-5)=1/2(x-4)

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Solution for 7x+13-(4x-5)=1/2(x-4) equation: 



7x+13-(4x-5)=1/2(x-4)

We move all terms to the left:

7x+13-(4x-5)-(1/2(x-4))=0



Domain of the equation: 2(x-4))!=0

x∈R



We get rid of parentheses

7x-4x-(1/2(x-4))+5+13=0

We multiply all the terms by the denominator


7x*2(x-4))-4x*2(x-4))-(1+5*2(x-4))+13*2(x-4))=0

Wy multiply elements

28x^3(x-4))-(1+5*2(x-4))+13*2(x-4))=0

We do not support expression: x^3(x

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