(4x+4)/4=-(3x-1)/7

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Solution for (4x+4)/4=-(3x-1)/7 equation:



(4x+4)/4=-(3x-1)/7
We move all terms to the left:
(4x+4)/4-(-(3x-1)/7)=0
We calculate fractions
4x/()+(-(-(3x-1)*4)/()=0
We calculate terms in parentheses: +(-(-(3x-1)*4)/(), so:
-(-(3x-1)*4)/(
We multiply all the terms by the denominator
-(-(3x-1)*4)
We calculate terms in parentheses: -(-(3x-1)*4), so:
-(3x-1)*4
We multiply parentheses
-12x+4
Back to the equation:
-(-12x+4)
We get rid of parentheses
12x-4
Back to the equation:
+(12x-4)
We get rid of parentheses
4x/()+12x-4=0
We multiply all the terms by the denominator
4x+12x*()-4*()=0
We add all the numbers together, and all the variables
4x+12x*()=0

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