2s+5(3s-6)=6(5s-8)+12

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Solution for 2s+5(3s-6)=6(5s-8)+12 equation: 



2s+5(3s-6)=6(5s-8)+12

We move all terms to the left:

2s+5(3s-6)-(6(5s-8)+12)=0

We multiply parentheses

2s+15s-(6(5s-8)+12)-30=0



We calculate terms in parentheses: -(6(5s-8)+12), so:

6(5s-8)+12

We multiply parentheses

30s-48+12

We add all the numbers together, and all the variables

30s-36

Back to the equation:

-(30s-36)



We add all the numbers together, and all the variables

17s-(30s-36)-30=0

We get rid of parentheses

17s-30s+36-30=0

We add all the numbers together, and all the variables

-13s+6=0

We move all terms containing s to the left, all other terms to the right

-13s=-6

s=-6/-13

s=6/13

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