2x+19=2(3x-3)+5

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Solution for 2x+19=2(3x-3)+5 equation: 



2x+19=2(3x-3)+5

We move all terms to the left:

2x+19-(2(3x-3)+5)=0



We calculate terms in parentheses: -(2(3x-3)+5), so:

2(3x-3)+5

We multiply parentheses

6x-6+5

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

2x-6x+1+19=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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