2r-10=2(2r+3)

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Solution for 2r-10=2(2r+3) equation: 



2r-10=2(2r+3)

We move all terms to the left:

2r-10-(2(2r+3))=0



We calculate terms in parentheses: -(2(2r+3)), so:

2(2r+3)

We multiply parentheses

4r+6

Back to the equation:

-(4r+6)



We get rid of parentheses

2r-4r-6-10=0

We add all the numbers together, and all the variables

-2r-16=0

We move all terms containing r to the left, all other terms to the right

-2r=16

r=16/-2

r=-8

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