8(4-x)=8x+2

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Solution for 8(4-x)=8x+2 equation: 



8(4-x)=8x+2

We move all terms to the left:

8(4-x)-(8x+2)=0

We add all the numbers together, and all the variables

8(-1x+4)-(8x+2)=0

We multiply parentheses

-8x-(8x+2)+32=0

We get rid of parentheses

-8x-8x-2+32=0

We add all the numbers together, and all the variables

-16x+30=0

We move all terms containing x to the left, all other terms to the right

-16x=-30

x=-30/-16

x=1+7/8

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