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-4+2x=4+1/2x
We move all terms to the left:
-4+2x-(4+1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(1/2x+4)-4=0
We get rid of parentheses
2x-1/2x-4-4=0
We multiply all the terms by the denominator
2x*2x-4*2x-4*2x-1=0
Wy multiply elements
4x^2-8x-8x-1=0
We add all the numbers together, and all the variables
4x^2-16x-1=0
a = 4; b = -16; c = -1;
Δ = b2-4ac
Δ = -162-4·4·(-1)
Δ = 272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{272}=\sqrt{16*17}=\sqrt{16}*\sqrt{17}=4\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{17}}{2*4}=\frac{16-4\sqrt{17}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{17}}{2*4}=\frac{16+4\sqrt{17}}{8} $
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