2n+4(n-1)=2(6n-1)-7

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Solution for 2n+4(n-1)=2(6n-1)-7 equation: 



2n+4(n-1)=2(6n-1)-7

We move all terms to the left:

2n+4(n-1)-(2(6n-1)-7)=0

We multiply parentheses

2n+4n-(2(6n-1)-7)-4=0



We calculate terms in parentheses: -(2(6n-1)-7), so:

2(6n-1)-7

We multiply parentheses

12n-2-7

We add all the numbers together, and all the variables

12n-9

Back to the equation:

-(12n-9)



We add all the numbers together, and all the variables

6n-(12n-9)-4=0

We get rid of parentheses

6n-12n+9-4=0

We add all the numbers together, and all the variables

-6n+5=0

We move all terms containing n to the left, all other terms to the right

-6n=-5

n=-5/-6

n=5/6

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