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2k^2-2k-144=0
a = 2; b = -2; c = -144;
Δ = b2-4ac
Δ = -22-4·2·(-144)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-34}{2*2}=\frac{-32}{4} =-8 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+34}{2*2}=\frac{36}{4} =9 $
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