3/(x+4)=9/(2x-3)

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Solution for 3/(x+4)=9/(2x-3) equation: 



3/(x+4)=9/(2x-3)

We move all terms to the left:

3/(x+4)-(9/(2x-3))=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: (2x-3))!=0

x∈R



We calculate fractions


6x/((x+4)*(2x-3)))+(-(9*(x+4))/((x+4)*(2x-3)))=0



We calculate terms in parentheses: -(9*(x+4))/((x+4)*(2x-3))), so:

9*(x+4))/((x+4)*(2x-3))

We multiply all the terms by the denominator


9*(x+4))

We multiply parentheses

9x+

We add all the numbers together, and all the variables

9x

Back to the equation:

-(9x)



We add all the numbers together, and all the variables

-9x+6x/((x+4)*(2x-3)))+(=0

We multiply all the terms by the denominator


-9x*((x+4)*(2x-3)))+(+6x=0

We add all the numbers together, and all the variables

6x-9x*((x+4)*(2x-3)))+(=0

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