3(r+1)-r=2(r+5)-4

Solution for 3(r+1)-r=2(r+5)-4 equation:

3(r+1)-r=2(r+5)-4

We move all terms to the left:

3(r+1)-r-(2(r+5)-4)=0

We add all the numbers together, and all the variables

-1r+3(r+1)-(2(r+5)-4)=0

We multiply parentheses

-1r+3r-(2(r+5)-4)+3=0


We calculate terms in parentheses: -(2(r+5)-4), so:

2(r+5)-4

We multiply parentheses

2r+10-4

We add all the numbers together, and all the variables

2r+6

Back to the equation:

-(2r+6)


We add all the numbers together, and all the variables

2r-(2r+6)+3=0

We get rid of parentheses

2r-2r-6+3=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation