2k-3/2k+1=3k-5/3k+2

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Solution for 2k-3/2k+1=3k-5/3k+2 equation: 



2k-3/2k+1=3k-5/3k+2

We move all terms to the left:

2k-3/2k+1-(3k-5/3k+2)=0



Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R





Domain of the equation: 3k+2)!=0

k∈R



We get rid of parentheses

2k-3/2k-3k+5/3k-2+1=0

We calculate fractions


2k-3k+(-9k)/6k^2+10k/6k^2-2+1=0

We add all the numbers together, and all the variables

-1k+(-9k)/6k^2+10k/6k^2-1=0

We multiply all the terms by the denominator


-1k*6k^2+(-9k)+10k-1*6k^2=0

We add all the numbers together, and all the variables

10k-1k*6k^2+(-9k)-1*6k^2=0

Wy multiply elements

-6k^3-6k^2+10k+(-9k)=0

We get rid of parentheses

-6k^3-6k^2+10k-9k=0

We do not support ekpression: k^3

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