(3/4x-1)+(3/4x-2)=0

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Solution for (3/4x-1)+(3/4x-2)=0 equation: 



(3/4x-1)+(3/4x-2)=0



Domain of the equation: 4x-1)!=0

x∈R





Domain of the equation: 4x-2)!=0

x∈R



We get rid of parentheses

3/4x+3/4x-1-2=0

We multiply all the terms by the denominator


-1*4x-2*4x+3+3=0

We add all the numbers together, and all the variables

-1*4x-2*4x+6=0

Wy multiply elements

-4x-8x+6=0

We add all the numbers together, and all the variables

-12x+6=0

We move all terms containing x to the left, all other terms to the right

-12x=-6

x=-6/-12

x=1/2

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