y-4(3-2y)=7-(y+4)

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Solution for y-4(3-2y)=7-(y+4) equation: 



y-4(3-2y)=7-(y+4)

We move all terms to the left:

y-4(3-2y)-(7-(y+4))=0

We add all the numbers together, and all the variables

y-4(-2y+3)-(7-(y+4))=0

We multiply parentheses

y+8y-(7-(y+4))-12=0



We calculate terms in parentheses: -(7-(y+4)), so:

7-(y+4)

determiningTheFunctionDomain
-(y+4)+7

We get rid of parentheses

-y-4+7

We add all the numbers together, and all the variables

-1y+3

Back to the equation:

-(-1y+3)



We add all the numbers together, and all the variables

9y-(-1y+3)-12=0

We get rid of parentheses

9y+1y-3-12=0

We add all the numbers together, and all the variables

10y-15=0

We move all terms containing y to the left, all other terms to the right

10y=15

y=15/10

y=1+1/2

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