2k+4(k-4)=-2(2+4k)+2k

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Solution for 2k+4(k-4)=-2(2+4k)+2k equation: 



2k+4(k-4)=-2(2+4k)+2k

We move all terms to the left:

2k+4(k-4)-(-2(2+4k)+2k)=0

We add all the numbers together, and all the variables

2k+4(k-4)-(-2(4k+2)+2k)=0

We multiply parentheses

2k+4k-(-2(4k+2)+2k)-16=0



We calculate terms in parentheses: -(-2(4k+2)+2k), so:

-2(4k+2)+2k

We add all the numbers together, and all the variables

2k-2(4k+2)

We multiply parentheses

2k-8k-4

We add all the numbers together, and all the variables

-6k-4

Back to the equation:

-(-6k-4)



We add all the numbers together, and all the variables

6k-(-6k-4)-16=0

We get rid of parentheses

6k+6k+4-16=0

We add all the numbers together, and all the variables

12k-12=0

We move all terms containing k to the left, all other terms to the right

12k=12

k=12/12

k=1

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