12(r-2)=3(4r-11)+9

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Solution for 12(r-2)=3(4r-11)+9 equation: 



12(r-2)=3(4r-11)+9

We move all terms to the left:

12(r-2)-(3(4r-11)+9)=0

We multiply parentheses

12r-(3(4r-11)+9)-24=0



We calculate terms in parentheses: -(3(4r-11)+9), so:

3(4r-11)+9

We multiply parentheses

12r-33+9

We add all the numbers together, and all the variables

12r-24

Back to the equation:

-(12r-24)



We get rid of parentheses

12r-12r+24-24=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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