8-(n-8)=4(n+3)

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Solution for 8-(n-8)=4(n+3) equation: 



8-(n-8)=4(n+3)

We move all terms to the left:

8-(n-8)-(4(n+3))=0

We get rid of parentheses

-n-(4(n+3))+8+8=0



We calculate terms in parentheses: -(4(n+3)), so:

4(n+3)

We multiply parentheses

4n+12

Back to the equation:

-(4n+12)



We add all the numbers together, and all the variables

-1n-(4n+12)+16=0

We get rid of parentheses

-1n-4n-12+16=0

We add all the numbers together, and all the variables

-5n+4=0

We move all terms containing n to the left, all other terms to the right

-5n=-4

n=-4/-5

n=4/5

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