2b+4(b-6)=-2(2b+14)+98

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Solution for 2b+4(b-6)=-2(2b+14)+98 equation: 



2b+4(b-6)=-2(2b+14)+98

We move all terms to the left:

2b+4(b-6)-(-2(2b+14)+98)=0

We multiply parentheses

2b+4b-(-2(2b+14)+98)-24=0



We calculate terms in parentheses: -(-2(2b+14)+98), so:

-2(2b+14)+98

We multiply parentheses

-4b-28+98

We add all the numbers together, and all the variables

-4b+70

Back to the equation:

-(-4b+70)



We add all the numbers together, and all the variables

6b-(-4b+70)-24=0

We get rid of parentheses

6b+4b-70-24=0

We add all the numbers together, and all the variables

10b-94=0

We move all terms containing b to the left, all other terms to the right

10b=94

b=94/10

b=9+2/5

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