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(2x-24)(2x-18)=0
We multiply parentheses ..
(+4x^2-36x-48x+432)=0
We get rid of parentheses
4x^2-36x-48x+432=0
We add all the numbers together, and all the variables
4x^2-84x+432=0
a = 4; b = -84; c = +432;
Δ = b2-4ac
Δ = -842-4·4·432
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-12}{2*4}=\frac{72}{8} =9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+12}{2*4}=\frac{96}{8} =12 $
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