2(-x-5)=3(2x+2)

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Solution for 2(-x-5)=3(2x+2) equation: 



2(-x-5)=3(2x+2)

We move all terms to the left:

2(-x-5)-(3(2x+2))=0

We add all the numbers together, and all the variables

2(-1x-5)-(3(2x+2))=0

We multiply parentheses

-2x-(3(2x+2))-10=0



We calculate terms in parentheses: -(3(2x+2)), so:

3(2x+2)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

-2x-6x-6-10=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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