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1/3x+2=7x
We move all terms to the left:
1/3x+2-(7x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-7x+1/3x+2=0
We multiply all the terms by the denominator
-7x*3x+2*3x+1=0
Wy multiply elements
-21x^2+6x+1=0
a = -21; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·(-21)·1
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{30}}{2*-21}=\frac{-6-2\sqrt{30}}{-42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{30}}{2*-21}=\frac{-6+2\sqrt{30}}{-42} $
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