2a*a+12a=3a*a

Solution for 2a*a+12a=3a*a equation:

2a*a+12a=3a*a

We move all terms to the left:

2a*a+12a-(3a*a)=0

We add all the numbers together, and all the variables

2a*a+12a-(+3a*a)=0

We add all the numbers together, and all the variables

12a+2a*a-(+3a*a)=0

Wy multiply elements

2a^2+12a-(+3a*a)=0

We get rid of parentheses

2a^2+12a-3a*a=0

Wy multiply elements

2a^2-3a^2+12a=0

We add all the numbers together, and all the variables

-1a^2+12a=0

a = -1; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-1)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-1}=\frac{-24}{-2}
=+12
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-1}=\frac{0}{-2}
=0
$