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5x-2/2x=4
We move all terms to the left:
5x-2/2x-(4)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
5x*2x-4*2x-2=0
Wy multiply elements
10x^2-8x-2=0
a = 10; b = -8; c = -2;
Δ = b2-4ac
Δ = -82-4·10·(-2)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12}{2*10}=\frac{-4}{20} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12}{2*10}=\frac{20}{20} =1 $
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